What is the heat of vaporization for benzene?

What is the heat of vaporization for benzene?

30.8 kJ/mol
For benzene (C6H6), the normal boiling point is 80.1 °C and the enthalpy of vaporization is 30.8 kJ/mol.

What is the specific heat of benzene?

Chemical, physical and thermal properties of benzene, also called benzol. Phase diagram included.

Property Value Unit
Heat (enthalpy) of evaporation 33.8 kJ/mol
Specific heat capacity, Cp (gas) 82.4 J/mol K
Specific heat capacity, Cp (liquid) 133 J/mol K
Specific heat capacity, Cp (solid) at 32°F/0°C 118 J/mol K

What is the heat of vaporization of hydrogen?

0.44936 kJ/mol
Latent Heat of Vaporization of Hydrogen is 0.44936 kJ/mol.

What is the critical temperature of hydrogen sulfide?

212.7° F

Molecular Weight: 34.08
Critical Temperature: 212.7° F
Critical Pressure: 1309 psia
Critical Density: 0.349 g/ml
Latent Heat of Vaporization @ b.p.: 4.463 kcal/mol

What is the molar heat of fusion of benzene?

Molar ΔH (kJ/mol)

Substance heat of fusion ΔHfus (kJ/mol) heat of vaporization ΔHvap (kJ/mol)
aluminum 8.66 307.6
benzene 10.0 30.5
copper 13.2 322.1
gold 13.2 310.9

What is the heat of formation of benzene?

⇒ Heat of formation of Benzene is +14 K. Cal.

How do you calculate delta H vaporization?

The Enthalpy of Condensation

  1. First, convert 100°C to Kelvin. °C + 273.15 = K.
  2. Find the amount involved (in moles). nwater=PVRT=(1.0atm)(2.055L)(0.08206Latmmol−1K−1)(373.15K)=0.0671mol.
  3. Find ΔHcond. ΔHcond=−ΔHvap.
  4. Using the ΔHcond of water and the amount in moles, calculate the amount of heat involved in the reaction.

What is the vapor density of H2S?

1.537
The interpolated value for the vapor density of hydrogen sulphide under standard conditions was found to be 1.537.

What are the properties of H2S?

Hydrogen sulfide is a colorless, flammable, extremely hazardous gas with a “rot- ten egg” smell. Some common names for the gas include sewer gas, stink damp, swamp gas and manure gas. It occurs naturally in crude petroleum, natural gas, and hot springs.

What is the heat of vaporization of benzene in calories per mole?

7350 calorieK-‘mol-
Heat of vapourisation of benzene is 7350 calorieK-‘mol-1.

Why is the heat of vaporization higher than that of fusion?

The latent heat of vaporization is higher than the latent heat of fusion since gas molecules have the largest intermolecular space and the force of attraction between the molecules is almost negligible. Therefore, more energy is required to convert liquid to gas.

What is the vapour pressure of benzene?

The vapour pressure of pure benzene is 639.7 mm Hg and the vapour pressure of a solution of a solute in benzene at the temperature is 631.9 mm Hg.

Why benzene has less heat of formation?

The heat of hydrogenation is less than expected because benzene is stabilized by resonance. Cyclohexene has one double bond, and its heat of hydrogenation is -120 kJ/mol. Benzene has three double bonds, so we might expect its heat of hydrogenation to be -360 kJ/mol.

How do you calculate the heat of combustion of benzene?

The enthalpy of combustion of benzene from the following data will be:

  1. 6C(s)+3H2​(g)→C6​H6​(l);ΔH=+45. 9kJ.
  2. H2​(g)+21​O2​(g)→H2​O(l);ΔH=−285. 9kJ.
  3. C(s)+O2​(g)→CO2​(g);ΔH=−393. 5kJ.

How do you find the heat of vaporization using the Clausius Clapeyron equation?

Solution

  1. Step 1: Convert °C to K. TK = °C + 273.15. T1 = 14.7 °C + 273.15. T1 = 287.85 K. T2 = 52.8 °C + 273.15.
  2. Step 2: Find PT2,vap. ln[10 torr/PT2,vap] = (47.2 kJ/mol/0.008314 kJ/K·mol)[1/325.95 K – 1/287.85 K] ln[10 torr/PT2,vap] = 5677(-4.06 x 10-4) ln[10 torr/PT2,vap] = -2.305.
  • July 27, 2022